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-rw-r--r--debian/apt.auto-removal.sh18
1 files changed, 18 insertions, 0 deletions
diff --git a/debian/apt.auto-removal.sh b/debian/apt.auto-removal.sh
index e1b1c92d4..f44a11384 100644
--- a/debian/apt.auto-removal.sh
+++ b/debian/apt.auto-removal.sh
@@ -9,6 +9,10 @@ set -e
# - the kernel version we've been called for
# - the latest kernel version (determined using rules copied from the grub
# package for deciding which kernel to boot)
+# - the second-latest kernel version, if the booted kernel version is
+# already the latest and this script is called for that same version,
+# to ensure a fallback remains available in the event the newly-installed
+# kernel at this ABI fails to boot
# In the common case, this results in exactly two kernels saved, but it can
# result in three kernels being saved. It's better to err on the side of
# saving too many kernels than saving too few.
@@ -41,16 +45,30 @@ version_test_gt ()
list=$(${DPKG} -l 'linux-image-[0-9]*'|awk '/^ii/ { print $2 }' | sed -e's/linux-image-//')
latest_version=""
+previous_version=""
for i in $list; do
if version_test_gt "$i" "$latest_version"; then
+ previous_version="$latest_version"
latest_version="$i"
+ elif version_test_gt "$i" "$previous_version"; then
+ previous_version="$i"
fi
done
+if [ "$latest_version" != "$installed_version" ] \
+ || [ "$latest_version" != "$running_version" ] \
+ || [ "$installed_version" != "$running_version" ]
+then
+ # We have at least two kernels that we have reason to think the
+ # user wants, so don't save the second-newest version.
+ previous_version=
+fi
+
kernels=$(sort -u <<EOF
$latest_version
$installed_version
$running_version
+$previous_version
EOF
)